Question

preform the addition and simplify: (tan x/ csc x)+(sin x/tan x)

Answer 1

break everything down in terms of sin/cos, then add

Answer 2

cosX?

Answer 3

Yup, putting everything in terms of sin and cos is often a good strategy.

Answer 4

no, I get 1/cosx + 1/cosx

Answer 5

Which is 2/cosx or 2secx

Answer 6

but those aren't any of the answers ?

Answer 7

Hm, what are the options?

Answer 8

cosx
secx
csc^2x
sec^2x

Answer 9

So, if I find a common denominator of cscxtanx, I come out with a different answer.

Answer 10

Kinda weird, but let me know how it goes.

Answer 11

yeah idk

Answer 12

Did you use the common denominator and add the fractions?

Answer 13

if it becomes common denominator 2 cosx but I think that's an error

Answer 14

I started over and used a common denominator of cscxtanx and got one of the answers you listed.

Answer 15

sec^2x ?

Answer 16

No, did you try adding the fractions?

Answer 17

I got tan^2x/cscxtanx + sinxcscx/cscxtanx as the first step.

Answer 18

Which gives (tan^2x+sinxcscx)/cscxtanx

Answer 19

From there, sinxcscx is 1.

Answer 20

im lost lol like im never gonna finish this:(

Answer 21

This one is a tricky one. It might help to review adding fractions, but I know you are running out of time.

Answer 22

[tan/csc] + [sin/tan)]

[(sin/cos)/(1/sin)] + [sin/(sin/cos)]

[sin^2/cos] + [cos]

[sin^2/cos] + [cos^2/cos]

Answer 23

And just telling you the answer isn't going to help you in the long run.

Answer 24

ik trust me ik

Answer 25

combine the fractions,

Answer 26

:) Keep practicing!

Answer 27

Are you calling it a nigh?

Answer 28

*night

Answer 29

no I cant cuz I have other work to but I really have to get this done

Answer 30

(use sin^2+cos^2=1)

Answer 31

UncleRhaukus' method looks good. Maybe you could follow his better.

Answer 32

ughh im so confused

Answer 33

What is it that is confusing?

Answer 34

idk its just not clicking

Answer 35

It's a lot of trial and error at first, and that can be frustrating. The more you practice, the more you will recognize the trends.

Answer 36

Maybe move on to the next problem and come back to this one if you can?

Answer 37

tan^2x +1 +csc^2x

Answer 38

tan^2x +1 = csc^2x

Answer 39

sec^2x mybad

Answer 40

Ok. Check your pythagorean identities.

Answer 41

Also, when you have an equals sign, you just want each side to look the same.

Answer 42

tan^2 +1 = sec^2
convert to sin and cos
tan =sin/cos, sec=1/cos

then multiply by both sides by cos^2

Answer 43

so SEC^4x

Answer 44

omg this is so hard

Answer 45

You can do it!

Answer 46

tan^2x + 1 = sec^2x
sin^2x/cos^2x + 1 = 1/cos^2x

Answer 47

Do you see how I just changed everything into sin and cos?

Answer 48

yes

Answer 49

If I multiply the whole equation by cos^2x, I get
sin^2x + cos^2x = 1

Answer 50

Which is the pythagorean identity.

Answer 51

So, essentially, 1=1.

Answer 52

yes but that's not an answer im given to shoose from

Answer 53

what are your options?

Answer 54

csc^2x
cosx
sec^2x
secx

Answer 55

Are there instructions on leaving one side alone and only working with the other side?

Answer 56

it only says perform addition and simplify thers no equal sine the : from my question is just seperatin of the problems and words

Answer 57

No equal sign? What does the original problem say then?

Answer 58

exactly what I posted

Answer 59

This one? tan^2x +1 +csc^2x

Answer 60

no (tanx/cscx)+(sinx/tanx)

Answer 61

Oh, I thought you started a new problem. Sorry.

Answer 62

no lol

Answer 63

Let's try again. I messed up the first time through on this one.

Answer 64

Changing everything into sin and cos gives (sinx/cox)/(1/sinx) + sinx/(sinx/cosx)

Answer 65

Does that make sense so far?