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Mathematics 23 Online
OpenStudy (anonymous):

help? Find the difference quotient and simplify your answer.

OpenStudy (anonymous):

OpenStudy (anonymous):

So it's asking for: \[f(s) = -8s^2 - 7s\] and it's giving you conditions for the variable s. Let's do the easier portion first. \[f(3) = -8(3)^2 - 7(3) = -8(9) -21 = -72 -21 = -93\]

OpenStudy (anonymous):

The part you probably had difficulty with looks like this: \[f(3+h) = -8(3+h)^2 -(3+h)\] Simplifying we get: \[=-8(9+6h+h^2) -3-h\] \[=-72 -48h -h^2 -3 - h = -h^2 -49h -75\]

OpenStudy (anonymous):

Now just plug it in to the main equation \[\frac{f(3+h)-f(3) }{h } = \frac{ -h^2-49h-75-93 }{h }\] simplified: \[\frac{ -h^2-49h-168 }{h } or \frac{ h^2+49h+168 }{ -h }\]

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

Glad to help!

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