Question

any idea guys ??
if
M = 1234567891011121314...20122013
then
how many digits are there of M^2

Answer 1

@robtobey , @CGGURUMANJUNATH

Answer 2

@TuringTest

Answer 3

have you tried it on you're calculator?

Answer 4

it doesnt work, it says error :)

Answer 5

hmm what is the full number?

Answer 6

oh i see the number hmm

Answer 7

it is the first time i see this question, so i dont know how to evaluate it

Answer 8

sorry can't help you there.

Answer 9

\[1^{2}=1....1 digit\]
\[12^{2}=144....3 digits\]
\[123^{2}=15129...5 digits\]
\[1234^{2}=1522756.....7 digits\]
\[12345^{2}=152399025....9 digits\]
Now getting some idea...

Answer 10

oh, so i have to know how many digits of M, first ?

Answer 11

if so then
if M incluading n digits then there are (2n-1) digits are there in M^2. am i right ?

Answer 12

ya...now try finding the no. of digits...

Answer 13

ok, thank you. i got it :)