any idea guys ??
if
M = 1234567891011121314...20122013
then
how many digits are there of M^2

Question

any idea guys ??
if
M = 1234567891011121314...20122013
then 
how many digits are there of M^2

anonymous · Answer

@robtobey , @CGGURUMANJUNATH

anonymous · Answer

@TuringTest

anonymous · Answer

have you tried it on you're calculator?

anonymous · Answer

it doesnt work, it says error :)

anonymous · Answer

hmm what is the full number?

anonymous · Answer

oh i see the number hmm

anonymous · Answer

it is the first time i see this question, so i dont know how to evaluate it

anonymous · Answer

sorry can't help you there.

anonymous · Answer

$$1^{2}=1....1 digit$$
$$12^{2}=144....3 digits$$
$$123^{2}=15129...5 digits$$
$$1234^{2}=1522756.....7 digits$$
$$12345^{2}=152399025....9 digits$$
Now getting some idea...

anonymous · Answer

oh, so i have to know how many digits of M, first ?

anonymous · Answer

if so then 
if M incluading n digits then there are (2n-1) digits are there in M^2. am i right ?

anonymous · Answer

ya...now try finding the no. of digits...

anonymous · Answer

ok, thank you. i got it :)