solve the following on the interval (0, 306) 2sec^2x-secx+3=0

Question

anonymous · Answer

what do you mean by that?

anonymous · Answer

No, i started out by simplifying it but i don't think i did it right

anonymous · Answer

I did this:
2sec^2-secx=3
divided 2 to the other side
took the square root of sec^2 and 3/2

anonymous · Answer

now I'm a little stumped

anonymous · Answer

2sec^2x-secx=t

anonymous · Answer

or t+3=0

loser66 · Answer

oops, I am sorry, you have a complex number

anonymous · Answer

Did i do it wrong in the first place ?

loser66 · Answer

please recheck your problem, first off , the interval (0, 306) ??? or (0, 360) ??
 second the equation 2sec^2 (x) - sec(x) +3 =0 or sec ^2 (x) - 2sec (x) +3 =0??

anonymous · Answer

(0,360) oops.

loser66 · Answer

and the equation?

anonymous · Answer

2sec^2x-secx+3=0

anonymous · Answer

I'm supposer to get multiple answers for x if that helps

loser66 · Answer

wow, I am stuck at complex number. http://www.wolframalpha.com/input/?i=2sec^2x+-sec+x+%2B3+%3D0

anonymous · Answer

oh no that doesn't look so good, it's ok thank you for trying i really appreciate it!

loser66 · Answer

hehehe, I tried and stuck . Then, I looked for the reason, it gave me the reason, hehehe... I failed!! hehehehe I am sorry for being helpless

anonymous · Answer

You weren't helpless! at least you tried ! Thank you- i'll ask my teacher tomorrow howl to solve it

anonymous · Answer

you need to sub tract the 3 then factor to get so you can het something that looks like this (a+1)(a-1) you get what im saying ?