Question

Chelsea is trying to find the equation of a quadratic that has a focus of (1, 3) and a directrix of y = −3. Describe to Chelsea your preferred method for deriving the equation. Make sure you use Chelsea's situation as a model to help her understand.

Answer 1

@phi

Answer 2

ax^2+bx^1+c

Answer 3

Directrix of y = -3 indicates a vertical parabola. It opens up or down.
Focus (1,3) now indicates three things:
1) Axis of symmetry is x = 1
2) Focus is (1,0)
3) Parabola opens UP.

Answer 4

@HAPPYSTUDYING!!!!!

Answer 5

which values are a b and c? @_CALCULATOR_

Answer 6

use the distance formula

Answer 7

\[\sqrt{(x2 - x1) + (y2 - y1)}\]
this one?

Answer 8

yeah

Answer 9

what are my second set of cordinates?

Answer 10

@radar can u help

Answer 11

try this \[\sqrt{(x0-a)^{2}+(y0-b)^{2}}\]

Answer 12

so substitute
(1-a)2+(3-b)2

Answer 13

hmm... 1a + 9b.... 10ab.... sqrt... 3.162