Question

Trinomial help:(

Answer 1

\[2n^2-20n+50\]

Answer 2

@jim_thompson5910

Answer 3

what is the GCF in this case?

Answer 4

2

Answer 5

Dear Lizzie, please type the instructions for the problem in question, along with the mathematical expression. Doing so might actually the the problem easier for you yourself to approach. Jim is on the right track in asking you to identify the greatest common factor. It follows that solving this problem completely will entail finding all the factors, including Jim's GCF.

Answer 6

so factor out the GCF to get

\[\Large 2n^2 - 20n + 50\]

\[\Large 2(n^2 - 10n + 25)\]

what's the next step?

Answer 7

it's ok mathmale, I know what the instructions are but thanks for pointing it out

Answer 8

You two are doing fine on your own. I'll step out.

Answer 9

Thanks!!

Answer 10

Don't you have to put something in two different parentasis?

Answer 11

yes

Answer 12

how would you factor \(\Large n^2 - 10n + 25\)

Answer 13

2(n-5)(n-5) ??

Answer 14

perfect

Answer 15

you nailed it

Answer 16

you can also write that as \(\Large 2(n-5)^2\)

Answer 17

ok

Answer 18

\[1-4x^2\]

Answer 19

how would you do this?

Answer 20

hint:

a^2 - b^2 = (a-b)(a+b)

difference of squares rule

Answer 21

sorry, i don't get it...

Answer 22

hint #2: \(\Large 1 = 1^2\)

hint #3: \(\Large 4x^2 = 2^2x^2 = (2x)^2\)

Answer 23

so you can rewrite

\[\Large 1 - 4x^2\]

as

\[\Large 1^2 - (2x)^2\]

and I'll let you take over from here

Answer 24

would it be \[-(2x)^2\]

Answer 25

in this case,

a = 1
b = 2x

Answer 26

so plug those values into a^2 - b^2 = (a-b)(a+b)

Answer 27

ok so (1+2x)(1-2x)

Answer 28

bingo

Answer 29

haha thxs

Answer 30

so whenever you have a difference of squares, use the factoring rule a^2 - b^2 = (a-b)(a+b)

Answer 31

ok let me try getting the next one...

Answer 32

ok

Answer 33

Ok so my next one is \[144-25x^2\]

Then it goes \[(144+25x)(144-25x)\]

But idk what to do next...

Answer 34

You no what i figured it out... :D

Answer 35

no, remember that

144 = 12^2

25x^2 = (5x)^2

Answer 36

what did you get

Answer 37

(12+5x)(12-5x)

Answer 38

right?

Answer 39

yep that is correct

Answer 40

So my next one is \[125v^2-320\]

And i went to (320+125v)(320-125v)

then i divided it by 5 and got : (64+25v)(64-25v)

But that is not correct.

Answer 41

first factor out the GCF

Answer 42

would it be 5

Answer 43

correct, so what do you get when you factor out 5?

Answer 44

\[5(25v^2-64)\]

Answer 45

now factor that difference of squares

Answer 46

5(v-8)(v+8) ?

Answer 47

(64+25v)(64-25v) wait would it be this?

Answer 48

not quite

Answer 49

oh wait

Answer 50

the first one was closer, but still not there

Answer 51

5(5v-8)(5v+8)

Answer 52

perfect

Answer 53

I have more questions, but i have to go. Another time??

Answer 54

sure, that works for me

Answer 55

Thanks for all help, Jim!!

Answer 56

yw, have a good night

Answer 57

You too!! Good night and God bless:D