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Mathematics 18 Online
OpenStudy (anonymous):

find the where the function increases and deceases f(x)=tanx

OpenStudy (anonymous):

hi pretty, will u gimme a medal for this?

OpenStudy (anonymous):

f'(x)<0, graph is decreasing , f'(x)=0, it is not decereasing or increaasing, f'(x)>0, it is increasing

OpenStudy (anonymous):

BAM goes the answer

OpenStudy (anonymous):

are there # because Tangent Function: One cycle occurs between -pi/2 and pi/2 . There are vertical asymptotes at each end of the cycle. The asymptote that occurs at pi/2repeats every Pi units. period: pi amplitude: none, graphs go on forever in vertical directions.

OpenStudy (anonymous):

cohesive, that was beautiful description

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

hmm that sdeont really answer my question, im suppose to find the largest intervals on which f is increasing and decreasing between -pi/2<x<pi/2

OpenStudy (anonymous):

for starters, f nvr decreases.

OpenStudy (anonymous):

for tanx

OpenStudy (anonymous):

please explain :)

OpenStudy (anonymous):

tan x only increases back to my example •intervals of increase/decrease: over one period and from -pi/2 to pi/2, tan (x) is increasing

OpenStudy (anonymous):

@JoannaBlackwelder can you help explain plz

OpenStudy (joannablackwelder):

Look at the graph. From left to right, it always rises. Thus it is increasing everywhere.

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