A cat with a mass of 4.50 kilograms sits on a ledge 0.800 meters above the ground. If it jumps to the ground, how much kinetic energy will it have just as it reaches the ground?

Question

anonymous · Answer

Ok, in this question, you have to think about conservation of energy. Initially, the cat only has potential energy (U=mgh). Just as the cat reaches the ground, it has kinetic energy (KE=0.5mv^2). Set the two equal to each other and you get mgh=KE. Sub in values and you get:
 4.5kg*0.8m*9.81=KE. The answer should be 35.3J.

anonymous · Answer

Oh wow, that's right. Man I wish I could have figured this out :/ I'm almost done with High School haha, thank you sir.

anonymous · Answer

LOL. It's "miss", but no problem all the same. ;D

anonymous · Answer

Oh D: I saw "james" but I didn't know you were a miss ;P Well how old are you?

anonymous · Answer

HAHAHA! That is a-okay, I just reeeeally like Star Trek. Anyways, glad my  answer helped. Ta!

anonymous · Answer

Oh, I see. Well I really like learning. My name means the Latin God of Darkness. I have it for everything really. Thanks again for the answer. Later ~

anonymous · Answer

Had this same question still dont understand how its 35.3 I use PE=mgh and Got 3.60