Question

3=log(2x-1)

Answer 1

You've already asked this.. I hope you're not just looking for answers..

Answer 2

umm this is my first question and post my teacher is out I need someone to help me how are you going to tell me I asked this already?

Answer 3

\[\huge \log_a x = n ---> x = a^n\]
use this rule.

Answer 4

\[\huge \log_{10} (2x-1) = 3\]

Answer 5

Sham, you help I suppose.

Answer 6

thank you

Answer 7

what would be my next step?

Answer 8

Use the rule.
let (2x-1) = x\[\huge \log_{10} (x) = 3\]

Answer 9

Work with me here.

Answer 10

im trying im sorry

Answer 11

\[\huge \log_a (x) = n ----> x = a^n\]

Answer 12

What?

Answer 13

-_-
IF
\[\huge \log_{10}(2x-1) = 3\]
THEN
\[\huge 2x-1= 10^3\]
using that rule.
that's all the help i'll provide.
you have the rule right infront of you, it really is quite simple..

Answer 14

so 1001=2x?

Answer 15

yes

Answer 16

x=500.5?

Answer 17

yes

Answer 18

so 500.5 is my answer?
or what is my next step?

Answer 19

thats ur answer
x = 500.5