Question

Factor out the greatest common monomial: 14y4 - 15y3 + 8y2 -2y
A. 2(7y4 - 8y3 + 4y2 - y)
B. y(14y3 - 15y2 + 8y - 2)
C. 2y(7y3 - 8y2 + 4y - 1)
D. y4(14 - 15y-1 + 8y-2 - 2y-3)

Answer 1

what do you think?

Answer 2

The answer isn't D

Answer 3

Or A

Answer 4

C

Answer 5

why C? Is there any # that can be multiplied by 2 to obtain 15?

Answer 6

it cannot be C, because the 2 times 8 is not equal to 15
Look over choice C

Answer 7

\[14y^4 - 15y^3 + 8y^2 -2y\]\[y(14y^3 - 15y^2 + 8y^1 -2)\]\[2(14y^3 - 15y^2 + 8y -2)\]

Answer 8

oooh then its B

Answer 9

Yes.

Answer 10

:) ty

Answer 11

True or False: To factor a polynomial using the grouping method, factor out the common terms from the first two terms and then the last two terms in the polynomial.

Answer 12

Eliminate A, C and D because of the second term that they each form.

thats the prev question....

Answer 13

You mean?
\[14y^4 - 15y^3 + 8y^2 -2y\]

\[14y^4=y \times y \times y \times y \times 2 \times 7\]\[-15y^3=y \times y \times y \times 3 \times 5 \times (-1)\]\[8y^2=y \times y \times 2 \times 2 \times 2\]\[-2y=y \times 2 \times (-1)\]

Answer 14

Id really get the above statement.

Answer 15

is it true??

Answer 16

I don't get the statement, so I really can't say }word problems" is my weak spout.

give me a second...

Answer 17

Yes, TRUE.

Answer 18

I read it over, and yes.

Answer 19

thanks!

Answer 20

Anytime, I always try my best to help, although I am better at doing staff rather than explaining.