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OpenStudy (anonymous):
How do I find x on a triangle with an angle and a side that are known?
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OpenStudy (anonymous):
.
OpenStudy (anonymous):
I believe that I understand part of the process but when I get to a certain point I get lost. :/
OpenStudy (anonymous):
Wait a sec
OpenStudy (anonymous):
\[\sin(60)=opposite/hypotenuse\]
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OpenStudy (anonymous):
Is that what I need to use?
OpenStudy (anonymous):
Yes ^_^
OpenStudy (anonymous):
So when I plug my information into the equation it looks like \[\sin(60)=x/9\] . Correct?
OpenStudy (anonymous):
here is your ratio for a 60 deg triangle
|dw:1387298747605:dw|
OpenStudy (anonymous):
The equation then starts to look like: sin(60)=x/9
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OpenStudy (anonymous):
x is 1/2 of 9
OpenStudy (anonymous):
I do not understand. How did you come to that conclusion?
OpenStudy (anonymous):
@ehuman
OpenStudy (anonymous):
When u resolve a number u can resolve it in the horizontal direction (x-axis) and vertical direction (y-axis)
OpenStudy (anonymous):
by memorizing the most common triangle ratios
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OpenStudy (anonymous):
|dw:1387299118518:dw|
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