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Mathematics 23 Online
OpenStudy (anonymous):

How do I find x on a triangle with an angle and a side that are known?

OpenStudy (anonymous):

.

OpenStudy (anonymous):

I believe that I understand part of the process but when I get to a certain point I get lost. :/

OpenStudy (anonymous):

Wait a sec

OpenStudy (anonymous):

\[\sin(60)=opposite/hypotenuse\]

OpenStudy (anonymous):

I have a link that will help you: http://www.mathsisfun.com/algebra/trig-solving-asa-triangles.html

OpenStudy (anonymous):

Is that what I need to use?

OpenStudy (anonymous):

Yes ^_^

OpenStudy (anonymous):

So when I plug my information into the equation it looks like \[\sin(60)=x/9\] . Correct?

OpenStudy (anonymous):

here is your ratio for a 60 deg triangle |dw:1387298747605:dw|

OpenStudy (anonymous):

The equation then starts to look like: sin(60)=x/9

OpenStudy (anonymous):

x is 1/2 of 9

OpenStudy (anonymous):

I do not understand. How did you come to that conclusion?

OpenStudy (anonymous):

@ehuman

OpenStudy (anonymous):

When u resolve a number u can resolve it in the horizontal direction (x-axis) and vertical direction (y-axis)

OpenStudy (anonymous):

by memorizing the most common triangle ratios

OpenStudy (anonymous):

|dw:1387299118518:dw|

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