Question

solve for all valid values of x

Answer 1

\[\log_{12} [(x)(x-4)]=1\]\[12^{1} = x^2-4x\]\[x^2-4x-12=0\]\[(x+2)(x-6)=0\]Roots are -2 and 6. But x cannot be -2 because that would make the log functions invalide. So \[x=6\]