Find the difference quotient f(x+h)-f(x)/h , where h is not equal to zero for the function below: f(x)=5X^2 +3X Simplify the answer as much as possible.
bunch of algebra ready?
oh Yes. I have been trying to work it out but it is confusing.
ok we have \(f(x)=5x^2+3x\) so the first thing we need to compute it \[f(x+h)=5(x+h)^2+3(x+h)\] by "compute" i really mean remove the parentheses
make sure to square carefully, and don't forget to distribute the \(3\) \[f(x+h)=5(x+h)^2-3(x+h)\] \[f(x+h)=5(x+h)(x+h)+3(x+h)\] \[f(x+h)=5(x^2+2xh+h^2)+3x+3h\] and finally \[f(x+h)=5x^2+10xh+5h^2+3x+3x\] so far so good?
typo on the last line, should have been \[f(x+h)=5x^2+10xh+5h^2+3x+3h\]
you ok to this step? we are not done yet
So far makes perfect sense
from this we have to subtract \(f(x)\) again more algebra, don't forget to distribute the minus sign \[f(x+h)-f(x)=5x^2+10xh+5h^2+3x+3h-(5x^2+3x)\] \[f(x+h)-f(x)=f(x+h)=5x^2+10xh+5h^2+3x+3h-5x^2-3x\]
ok i see
another damn typo \[f(x+h)-f(x)=5x^2+10xh+5h^2+3x+3h-5x^2-3x\]
when you subtract, all terms without an \(h\) in them cancel (add up to zero) leaving only \[f(x+h)-f(x)=10xh+3h-5h^2\]
finally you have to divide everything by \(h\) since there is an \(h\) in each term, divide them one by one making \[\frac{f(x+h)-f(x)}{h}=10x+3-5h\]
That would be 10xh+3h-5h^2/h?
yes, but when you divide by \(h\) divide each term since they all have an \(h\) in them, and you will end up with no denominator
\[\frac{10xh+3h-5h^2}{h}=10x+3-5h\]
ok I understand
Thanks so much for your help you explained it very clearly.
@satellite73 shouldn't \[5x^2+10xh+5h^2+3x+3h-5x^2-3x simplify \to 10xh+5h^2+3h\]?
@satellite73
yes, did i not write that?
oh damn, i had a minus sign there for no good reason you are right
ok. Just making sure. So my final answer is \[10x+5h+3\]
yes
Thanks again for your guidance.
Join our real-time social learning platform and learn together with your friends!