What is an expression for all possible angles coterminal with 30 degrees in general form?
30+360n, where n is an integer.
How did you figure that out? =)
Coterminal angles are angles that land in the same "spot" on the unit circle.
So, when you go one full rotation (to get back to the same spot), you travel 360 degrees either clockwise or counterclockwise.
And you can spin as many times as you want.
That is why n can be any integer.
Does that explanation help at all?
Yes. Thank you. =)
No worries
How about for 3 pi / 2?
Same concept applies, but for radians 1 rotation is 2π. Any ideas, guesses?
2 pi n + 3 pi/2?
Right, where n is an integer. Good job!
Awesome!
:)
Can I please ask you another question?
Sure.
For each angle in standard position, determine one positive and negative angle that is coterminal with it. pi/3
If you can write a formula for any cotermial angle, then you would just need to plug in two integers for n to find 2 coterminal angles, one positive and one negative.
also, the question with the 30 degree angle, does the expression lie in the domain\[-720 degrees \le \theta < 1080 \]?
That depends on what you choose for n.
but is that expression applicable here in general?
Not unless you restrict your n to only give you values in that domain.
then what can n be restricted to?
Whatever you need it to be. When n is 0, θ is 30, so that is in your domain. When n is -1, θ is -330, so that is good too.
When n is -2, θ is -690. Is that in the domain?
It should be.
For the other question and the coterminal angles.... pi/3, is there an easier way to solve it without plugging it in the formula?
Right. Could n be -3 and θ be in the domain?
Not that I know of off hand...
yes, it can because theta can be greater than 720 degrees and my answer is -1,050
I thought it couldn 't be less than -720.
\[-720 \le \theta < 1080\]
You don 't have to plug in every value though. You can skip if it seems you have enough room.
It looks good though.
For the other question and the coterminal angles.... pi/3, is there an easier way to solve it without plugging it in the formula?
You don 't have to plug in every value for n. You can skip if it seems you have enough room.
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