Question

Factor the following trinomial.

w^18 – 9w^9y^5 + 14y^10

Answer 1

\[w^{18}-9w^{9}y^{5}+14y^{10}\]

Answer 2

\[\textbf{Here is a huge guess, best wait till someone else helps but here is the guess:}\]
This is not a quadratic trinomial, so I may be wrong but here is my view:
\[w^{18}-9w^{9}y^{5}+14y^{10}\]
\[w^{18}-9w^{9}y^{5}+14y^{10}\]
Find two numbers that add up to 10 and multiply to 14.
In this case it is \(7+2=10\) and \(7\times2=14\).
So:
\[7y^5~and~2y^5\]
I don't really know what to do from there maybe someone else can help you better, sorry.
Here is the really guess part:
For \(w\):
The exponent is 9 and 18, we need to numbers that add up to 18 so:
9 + 9 = 18
Leaving us with:
\[w^9~and~w^9\]

Result:
\[(w^9+2y^5)(w^9+7y^5)\]

Answer 3

thank you