Question

Can any one help me to solve this GRE question...?

Answer 1

@SolomonZelman

Answer 2

a ratio of 4 mean in 1 day, to 7 men in 1 day

Answer 3

If you dont mind Can you explain in clearly plzzzz...@amistre64

Answer 4

still trying to work it out really. i just have a vague concept at the moment ....

(x+2)/(2x-1) = 4k

(x+2) = 4k(2x-1)

x+2 = 8kx-4k

0 = (8k-1)x - (4k+2)
-----------------------

2x-1 = 7k(x+5)

2x-1 = 7kx +35k

0 = (7k-2)x +(35k+1)
----------------------

(7k-2)x +(35k+1) = (8k-1)x - (4k+2)

(35k+1) = (8k-7k-1+2)x - (4k+2)

(35k+4k+1+2) = (8k-7k-1+2)x

39k+3 = (k+1)x

Answer 5

x number of men are working on a project. The work done by (x + 2) men in (2x - 1) days and the work done by (2x - 1) men in (x + 5) days is in the ratio 4:7

\[\frac{ (x + 2) }{ (2x - 1) } = 4\]
\[\frac{ (2x - 1) }{ (x + 5) } = 7\]
\[\frac{ (x + 2) }{ (2x - 1) } : \frac{ (2x - 1) }{ (x + 5) }\]
4 + 7 = 11
\[\frac{ (x + 2) }{ (2x - 1) } = \frac{ 4 }{ 11 }\]
\[\frac{ (2x - 1) }{ (x + 5) } = \frac{ 7 }{ 11 }\]

Hope this helps!

Answer 6

4:7 is a ratio in simplest terms; but any integer scalar k is just as good:

4k:7k

Answer 7

but Hear the given answer is x=2...

Answer 8

No it isn't @chetan552

Answer 9

I'm pretty sure they are saying (2x -1 ) = 2

Answer 10

if x = 2, we can solve outright

4 men in 7 days

3 men in 7 days

Answer 11

i dont have any ideas that are panning out.

Answer 12

Its ok thax for your help...

Answer 13

\[4\frac{ (x + 2) }{ (2x - 1) } : 7\frac{ (2x - 1) }{ (x + 5) }\]
is what i was trying to work with ... or some variant of it

Answer 14

(x+2)(2x−1)/(2x−1)(x+5)=4/7

I work with this i get the answer...

Answer 15

what is the answer? ive worked out something like A: x=6

Answer 16

There is a direct formula for this (M1*D1*H1)/W2=(M1*D1*H1)/W1


@amistre64

Answer 17

M= no. of mens
D=no. of days
H=no. of houers
W=work done.