Tell whether the following system has one solution, infinitely many solutions, or no solution.

x/4 + y/9 = 27
3x/2 + 2y/3 = 19

Question

Tell whether the following system has one solution, infinitely many solutions, or no solution. 

x/4 + y/9 = 27
3x/2 + 2y/3 = 19

anonymous · Answer

@primeralph @nonamenever @skullpatrol @chetan552 @MrNebula @amistre64

mrnebula · Answer

u like my help?

anonymous · Answer

Yes, please.

mrnebula · Answer

look like a code for a safe

anonymous · Answer

It says it has no solution but I need an explanation..?

anonymous · Answer

$$27 \neq 19$$
Thus it is no solution.

amistre64 · Answer

multiply the top and bottom by a common factor to get rid of the fractions

amistre64 · Answer

9,4,2,3  all seem to have 36 in common

36[x/4 + y/9 = 27]
36[3x/2 + 2y/3 = 19]


9x + 4y = 27(36)
3(18)x + 2(12)y = 19(36)


9x + 4y = 27(36)
3(2*9)x + 2(3*4)y = 19(36)  looks like we can factor out a 6 to 
                                            compare with

9x + 4y = 27(36)
9x + 4y = 19(6)

anonymous · Answer

For more detail explanation follow this link... http://www.algebra.com/algebra/homework/coordinate/Linear-systems.faq.question.320609.html

amistre64 · Answer

since both left had sides are exactly the same, the right hand sides would have to be identical as well

does 27(36) = 19(6) ??

anonymous · Answer

No it doesn't, I see what you mean.

amistre64 · Answer

this of course is not the only way toapproach this, it was just what was on the top of my head :)

anonymous · Answer

Well you explained it very well, thank you so much c:

amistre64 · Answer

youre welcome, and good luck :)

anonymous · Answer

Thanks c:

anonymous · Answer

@LanguageEnthusiast @chetan552  Thank you as well c: