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Trigonometry
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Prove the identity by changing the left side of the equation to show equivalency to the right side. Please show all steps. cos^4ø - sin^4ø = 1 - 2sin^2ø
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Hint: the left side of this equation is a "difference of two squares." Rewrite (cos 4*theta)^4 - (sin 4*theta)^4 as [(cos 4*theta)^2]^2 + [(cos 4*theta)^2]^2. Factor this by treating it as the difference of two squares. What do you think the next step should be?
I could think to factor it into (cos2(4x)+sin2(4x))(cos2(4x)−sin2(4x)) Am I on the right track?
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