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how many moles of aluminum are needed to react completely with 1.2 mol FeO? 2Al(s)+3FeO(s)->3Fe(s)+Al2O3(2)
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The numbers tell you that 2 moles of Al will react with 3 moles of FeO. The ratio is 2:3. Since you are starting with 1.2 moles of FeO, you need 1.2/3 x 2 = 0.8 moles of Al. Checking the answer, the ratio is 2:3 and you need less Al than FeO. Does this make sense? Hope this helps. http://answers.yahoo.com/question/index?qid=20100128100028AAMc4Df
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