9x^2 + 16x = 0
Well - One solution would be that x = 0.
and what would I do next?
I would use This -----> http://www.wolframalpha.com/input/?i=9x%5E2+%2B+16x+%3D+0 <-----
|dw:1387440292376:dw|
okay! and for this one would i need to use the imaginary letter i?
Nope - Not that I know of :)
OK thanks!
No problem! Take care!
@charlotte123 what about when I have to find the vertex?
@helpme1.2 do u know how to do it?
you want to find the x?
the c would be 0
I need to complete the square
to complete the square, find half the number of the b term and add it to both sides b in this case is 16
So it's: 9x^2 + 16x + 16 = 16 ?
no, take half of the b term, so you first divide 16 by 2 which equals 8 the 8 is what you should be adding, not 16
ohh that's be 64
9x^2 + 16x + 64 = 64
no, lets start all over again first lets divide everything by 9 so the x^2 would be simplified
|dw:1387431224169:dw|
9x^2 + 16x = 0 ---> divide every thing by 9 x^2 +16x/9 = 0 ----> now take have of the coefficient and square
x^2 +16x/9 + 64/81 = 0 +64/81
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