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Mathematics 8 Online
OpenStudy (anonymous):

9x^2 + 16x = 0

OpenStudy (charlotte123):

Well - One solution would be that x = 0.

OpenStudy (anonymous):

and what would I do next?

OpenStudy (charlotte123):

I would use This -----> http://www.wolframalpha.com/input/?i=9x%5E2+%2B+16x+%3D+0 <-----

OpenStudy (charlotte123):

|dw:1387440292376:dw|

OpenStudy (anonymous):

okay! and for this one would i need to use the imaginary letter i?

OpenStudy (charlotte123):

Nope - Not that I know of :)

OpenStudy (anonymous):

OK thanks!

OpenStudy (charlotte123):

No problem! Take care!

OpenStudy (anonymous):

@charlotte123 what about when I have to find the vertex?

OpenStudy (anonymous):

@helpme1.2 do u know how to do it?

OpenStudy (anonymous):

you want to find the x?

OpenStudy (anonymous):

the c would be 0

OpenStudy (anonymous):

I need to complete the square

OpenStudy (anonymous):

to complete the square, find half the number of the b term and add it to both sides b in this case is 16

OpenStudy (anonymous):

So it's: 9x^2 + 16x + 16 = 16 ?

OpenStudy (anonymous):

no, take half of the b term, so you first divide 16 by 2 which equals 8 the 8 is what you should be adding, not 16

OpenStudy (anonymous):

ohh that's be 64

OpenStudy (anonymous):

9x^2 + 16x + 64 = 64

OpenStudy (anonymous):

no, lets start all over again first lets divide everything by 9 so the x^2 would be simplified

OpenStudy (anonymous):

|dw:1387431224169:dw|

OpenStudy (anonymous):

9x^2 + 16x = 0 ---> divide every thing by 9 x^2 +16x/9 = 0 ----> now take have of the coefficient and square

OpenStudy (anonymous):

x^2 +16x/9 + 64/81 = 0 +64/81

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