Question

Write an equation for a sine curve that has the given amplitude and period, and which passes through the given point.

Amplitude 5, period 6, point (2, 0)

Answer 1

y= 5 sin (6x - pi/2)

y= 5 sin (3x - 3/2)

y= 5 sin ((pi/3)x - pi/2)

y= 5 sin ((pi/3)x - (2/3)pi)

Answer 2

I dont know how to convert the period and the point

Answer 3

\[\large y = a \sin k(x-b)\]they tell you a=5, and the period is 6.
\[\large period = \frac{ 2\pi }{ k }\]so find k.

Answer 4

is it y= 5 sin (6x - pi/2) ??

Answer 5

oh wait no

Answer 6

its y= 5 sin ((pi/3)x - (2/3)pi)

Answer 7

Once you have k, plug it in the formula, along with a=5, and plug in the point (2,0)
\[\large 0 = 5\sin k(2-b)\]find b

Answer 8

k is pi/3