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Mathematics 24 Online
OpenStudy (anonymous):

How do you find slope? (8,1) and (8, -4)

OpenStudy (opcode):

Slope for a straight line: \[m=\frac{y_2-y_1}{x_2-x_1}\]

OpenStudy (opcode):

@Me16 Do you know what to do from there?

OpenStudy (anonymous):

Yes Thank you

OpenStudy (opcode):

Okay, glad I could help if your confused just ask again :-).

OpenStudy (anonymous):

So the slope would be -5 right?

OpenStudy (opcode):

Okay so we have the points: \[(8, 1) (8, -4)\] \[m=\frac{1- (-4)}{8-8}\] \[m = \dfrac{5}{0}\] So the slope is undetermined since we have a zero.

OpenStudy (opcode):

For an undefined slope you will get zero in the denominator, which you cannot have because you cannot divide by zero. For a slope equal to zero, you will get a zero in the numerator. Zero divided by any non-zero denominator, will give you a slope of zero. (I copied this reasoning from mathref, so no credits to me just trying to explain my work :-).)

OpenStudy (anonymous):

I understand how the bottom is 0 but I thought it would be -5 because the formula says you put y2 in before y1 which would make it -4 - 1 = -5

OpenStudy (opcode):

If you graph -5 or 5 they will come out to be the same :-). \[(8,1)~(8, -4)\Rightarrow (x_2-x_1)\Rightarrow(8-8)\] \[(8,1)~(8, -4)\Rightarrow (y_2-y_1)\Rightarrow(1-(-4))\Rightarrow(-4 - 1)\] Either way is fine.

OpenStudy (anonymous):

So then the answer is 0?

OpenStudy (opcode):

No it is undefined since the zero is in the denominator. If the zero was in the numerator it would be 0.

OpenStudy (anonymous):

Ohh alright I think I understand now

OpenStudy (opcode):

Okay, great don't be afraid to ask any questions :-).

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