If the measure of arc AC is 140°, what is the measure of angle ABC?
ITs 40 degrees
angle ABC= 360 -140 -ACB - CAB
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@arabpride, without one more piece of data, how do you determine it is 40, and by proxy that the 2 remaining angles are 90? (which it is drawn semi to scale they cannot be) without knowing those are 90, how do we claim that they are?
i thought it was 360 - 140
They are tangents to the circle.
if B was closer or further from the circle than it is, that would not be true. there is nothing that says how far away B is so isn't that a huge assumption? where's the geometry/trig proof?
tangent to a circle is always at right angle to the radius of the circle at the point of contact.
ok so i got 360-140 = 220 ...
it cant be 220 because there are still two side angle unaccounted for
220 represent the 3 remaining angles. 2 of them will be identical but there are an infinite number of solutions until we know the distance that B is from the circle
sum of four angles of a quadrilateral =360 140+90+<ABC+90=360
how (mathematically) can you claim that the 2 side angles are 90? Im not trying to be a pain, just seeking to understand
shall i do 220 - 180?
they could be 89 degrees for all you know based on the info given...
my first answer is correct until more data is given
360 - 140 - the two unknown angles = andgle ABC
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I see your drawing where you "claim" that the sides are 90. I have yet to hear or see logical reason to accept it
what if they are 89 degrees? how do you prove it?
nothing states that they are right angles...
there are no right angles here
again, just seeking to understand, not just blindly accept
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