Question

How much heat is required to increase the temperature of 198.5 grams of water from 25.0 oC to 88.5 oC? (The specific heat of water is 4.18 J/g x oC)

Answer 1

Use the formula: \(\sf \color{limegreen}{Q = mc\Delta T}\)
m = mass
c = specific heat
\(\sf \Delta\)T = change in temperature (the difference)

Answer 2

so it'd be 198.5*25.0*88.5=? right?

Answer 3

No. You need to find \(\Delta\)T first before you can use the given equation above.

Answer 4

how do i do that

Answer 5

\(\Delta\)T is the difference between the two temperatures.

Answer 6

\(\Delta\)T = [T\(_2\)-T\(_1\)]

Answer 7

so it's be 63.5