Question

(14x^3-21x^2+28x)divided by (7x)

Answer 1

well you can treat is as 3 separate things

\[\frac{14x^3}{7x} -\frac{21x^2}{7x} + \frac{28x}{7x}\]

the rule for dividing the same base

\[\frac{x^a}{x^b} = x^{a - b}\]

subtract the powers...

hope this helps.

Answer 2

it said Find the quotient.

Answer 3

well this will give you the quotient...

here is the 1st term in the quotient...


\[\frac{14x^3}{7x} = 2x^2\]