Question

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Answer 1

14

Answer 2

Do you need help with part II?

Answer 3

Please look at what's done in the fourth column of the 2nd table, first row. The possible outcome is 2, and the probability of obtaining a 2 through the toss of two dice is 1/36. How did the author get 2/36 in the fourth column? Note: you could, if you wished, pretty much ignore the first column, as i is nothing more than a counter.

Answer 4

Now look at the next (the fourth) row. The possible outcome is 3, and the probability of obtaining such a result is 2/36. What are we supposed to do with these two figures?

Complete the entire table. Then add together all the products in Column 4. That result will be the mean value.

Answer 5

If the possible outcome in question is 3 and the probability of obtaining that 3 is 2/36, we'd need to multiply these two quantities together; wouldn't the result be (3)(2/36) = 6/36?

Answer 6

No "plugging in numbers" here. Rather, you'll need to ADD TOGETHER the 11 products in the fourth column. The result will be the mean value you were seeking.

Answer 7

You're welcome! Best of luck to you.