Which of the following is equal to sqrt(18x^9y^4)
I think its 3x^3y^2sqrt( 2)
like this? \[\sqrt{18x^{9y^4}}\]
Like this \(\sqrt{18x^9 y^4}\)
ok! ^_^
so, x^9 = (x^2)(x^2)(x^2)(x^2)(x) and if I do sqrt ( (x^2)(x^2)(x^2)(x^2)(x) ) I get?
I gotta leave soon, are you still here?
there?
\[sqrt(x^9)\]
sorry about that i have to keep refreshing to see what you type :p
it can equal that, it can also equal: sqrt ( (x^2)(x^2)(x^2)(x^2)(x) ) = x^4sqrt(x)
see, sqrt(x^2) = x if we have four x^2 under the square root, that is the same as having 4 x's outside the square root \[ \sqrt{(x^2)(x^2)(x^2)(x^2)(x)} = x(x)x(x)\sqrt{x} = x^4\sqrt{x}\]
so lets have you try the same thing with this: \[\sqrt{y^4} = \sqrt{y^?y^?} = y^?\]
I see I get it ! so y^2 y^2 = y^4
very good! make sure u dont' forget the square roots! \[\sqrt{y^4} = \sqrt{y^2y^2} = y^2\]
so we have taken care of the y's and the x's, all that is left to look at is the 18 so this is where we are to then: \[y(x^4)\sqrt{18x} \]
\[\sqrt{18x} = \sqrt{18}\sqrt{x}=\sqrt{2*9}\sqrt{x}=\sqrt{2}\sqrt{9}\sqrt{x}\]
\[3 \sqrt(2) \sqrt(x^9 y^4)\] Right?
that is a correct statment, but remember, we can reduce the sqrt(x^9y^4) part like we did before
I gotta go, i'm sorry! you've done great!
Ok thanks!
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