Question

@Luigi0210

What is the smallest possible sum of squares of two numbers if the product is -25?

Answer 1

Don't answer, let luigi try :D

Answer 2

oh god so sorry

Answer 3

-slaps bibby- bad

Answer 4

so luigi, where do u start?

Answer 5

I said don't answer, leave it for luigi -.-

Answer 6

this is a terrible question shamil

Answer 7

it's relatively easy.

Answer 8

terribly worded.

Answer 9

the product of two numbers is -25?

Answer 10

I'm only 12 man, give me a break.

Answer 11

LOL he's 12 guys

Answer 12

\[\huge xy = -25\]
\[\huge y = -25/x\]
\[\huge S = x^2 + y^2\]
\[\huge s(x) = x^2 + (\frac{ -25 }{ x })^2\]
minimize s(x)

Answer 13

what's up with people trying to insult one's intelligence here?

Answer 14

i'm not, more of a learning experience..

Answer 15

Oh I see.

Answer 16

so luigi, what do you get when you minimize s(x) ?
i'll do another step for you
\[\huge s(x) = x^2 + 625x^{-2}\]
take the first derivative and solve for x.

Answer 17

he claimed to be 12. You can't expect him to know calculus just yet

Answer 18

he's not 12, that was a joke, are you that gullible LOL

Answer 19

either that or it's sarcasm which i didnt catch on to

Answer 20

I still don't get how you're implying that a square can ever be negative

Answer 21

it's the internet. Then again how do i know for sure?

Answer 22

\[\LARGE s'(x)=2x+\frac{625}{3 (x^3)}\]

Let's just go along for the ride.. and yea, I'm 13, gosh.

Answer 23

*minus*

Answer 24

uh luigi
dat's wrong
\[\huge s'(x) = 2x -1250x^{-3}\]

Answer 25

Oh, fml -.-
Why do I have to be taught at night? xD

Answer 26

lol, now let's set the equation to equal zero and solve for x.

Answer 27

because if you don't answer, we will all make scary noises at you from your closet while your trying to sleep O:

Answer 28

x = pie!!

Answer 29

I still don't get how you're implying that a square can ever be negative

Answer 30

@sourwing its pi. lol

Answer 31

Okay, take 5 everyone.

Answer 32

\[\huge 2x - 1250x^{-3} = 0\]
\[\huge 2x = 1250x^{-3}\]
multiply both sides by x^3
\[\huge x^3(2x) = 1250x^{-3}(x^3)\]
\[\huge 2x^4 = 1250\]
\[\huge x^4 = 625\]
and....

Answer 33

I like pie better

Answer 34

Tis 5 ლ(■_■ლ)

Answer 35

plus or minus 5

Answer 36

but yes.

Answer 37

\[\huge S = x^2 + y^2\]
\[\huge y = -25/x\]
\[\huge y = -25/5 = -5\]
\[\huge x = \pm 5\]
\[\huge S = (5)^2 + (-5)^2\]
\[\huge S = 50\]

Answer 38

Now you dont HAVE to use calculus for this, i just wanted to show how it would be done lui

Answer 39

;-;

Answer 40

You write really horrible vague questions. this is a joke of a question. f u

Answer 41

LOL, my apologies master bibby.

Answer 42

Thank you for finally acknowledging me good day sirs