Question

how to make a modified calculator in C++ ????


please help ...

Answer 1

@Callisto

Answer 2

@dan815

Answer 3

please help...

Answer 4

hi

Answer 5

what do u want ur calculator to do

Answer 6

do you need to make interface for a calculator?? or actually write functions for calculator operations

Answer 7

yes

Answer 8

actually write functions for calculator operations

Answer 9

@dan815

Answer 10

@mathslover

Answer 11

@myininaya

Answer 12

Use math library, perhaps?

Answer 13

http://www.cplusplus.com/reference/cmath/

Answer 14

calculator that perform this

Answer 15

answer please

Answer 16

Can't see that clearly.

Answer 17

wait

Answer 18

here's my answer but i don't know how put the loop
#include <iostream>
using namespace std;
int main()
{
int a=0;
char op;
do { int number1, number2;
cout <<a<<endl;
cout << "Input a number: ";
cin >> number1;
cout << "Input a valid operator: ";
cin >> op;
cout << "Input another number: ";
cin >> number2;
switch (op) { case '+': cout << "The answer is: " << number1 + number2 << endl;
break;
case '-': cout << "The answer is: " << number1 - number2 << endl; break;
case '*': cout << "The answer is: " << number1 * number2 << endl; break;
case '/': cout << "The answer is: " << number1 / number2 <<endl;
break;
default: cout << "operator invalid." << endl;
}
cout<< "do you want to calculate again? (C or Q)";
cin >> op;
}
while (op == 'C');
return 0;
}

Answer 19

How do you know how many input numbers / operators are there for "one calculation"?

Answer 20

its depends to the users

Answer 21

what should i do to perform more than 2 numbers and operation by using loop

Answer 22

while (op != '=')

Answer 23

yes

Answer 24

nice ka...

Answer 25

thank you...

Answer 26

Huh? You got that?

Answer 27

awwww.

Answer 28

sorry there is still a lack...

Answer 29

the number are only performing 2 numbers

Answer 30

i need to perform 4 numbers in the second

Answer 31

lol, wait

Answer 32

okok

Answer 33

@ganeshie8

Answer 34

@Callisto

Answer 35

ok

Answer 36

It shouldn't work LOL

Answer 37

I think you need to rewrite your programme

Answer 38

its still the same

Answer 39

I mean you need to *rewrite* your programme.

Answer 40

can you help me??

Answer 41

I need to go soon...

Answer 42

#include <iostream> using namespace std; void main () { char choice='C'; do{ char symbol1; int count = 1, result1=0; int x, y; cout<<"Initial value= "<<result1<<endl;// this will display the initial value to the user cout<<"Input number: ";//input the two integers cin>>x; cout<<"Input operation: "; cin>>symbol1; cout<<"Input number: "; cin>>y; switch (symbol1) { case '+': result1= x + y; break; case '-' : result1 = x-y; break; case '/': result1 = x/y; break; case '*': result1 = x*y; } int a, result = result1; char symbol ; do{ cout<<"Input operation: "; cin>>symbol; if (symbol == '=') continue; cout<<"Input number: "; cin>>a; count++; switch (symbol) { case '+': result = result + a; break; case '-': result = result -a; break; case '/': result = result /a; break; case '*': result = result *a; break; } }while(symbol!='='); cout<<"Result: "<<result<<endl; cout<<"[Q]Quit or [C]Repeat Program\n"; do{cin>>choice; }while(choice!='C'&&choice!='c'&&choice!='q'&&choice!='Q'); cout<<endl<<endl; }while(choice=='C'||choice=='c'); }

Answer 43

please...

Answer 44

Do the order of operations matter?

Answer 45

If you do multiplications and divisions first, then this programme should work. I believe this is not good though. Feel free to modify it. Ask if you have any questions.

Answer 46

thanks :)