Question

Out of genuine curiosity, does d/dx of x^x=x^x?

Answer 1

My logic is that d/dx(x^x)= (x)(x^(x-1))= x^((x-1)+1)= x^x

Answer 2

\[y=x^x \]
Use log diff:
First step take log of both sides:
\[\ln(y)=\ln(x^x) => \ln(y) =x \ln(x) \]
Now differentiate both sides:
Then solve for y'

Answer 3

Anyways, I can finish the problem if you want

Answer 4

I don't want to waste any more of your time. You answered my curiosity, and that's all I needed. Thank you very much.

Answer 5

Np.