Question

Vertices could be (-x,0), (0,x), (x,0), and (0,-x).

Answer 1

whats the question?

Answer 2

I put the wrong thing, I'm sorry. This is the question I'm having trouble with: the coordinates for a rhombus are given as (2a,0), (0,2b), (-2a,0), and (0,-2b). Write a plan to prove that the midpoints of the sides of a rhombus determine a rectangle using coordinate geometry. Be sure to include the formulas.

Answer 3

This is for geometry btw.

Answer 4

alright lol thats what im in i might be able to help... maybe :)

Answer 5

Thank you!

Answer 6

i have the perfect picture that will help you i just do not know how to show it to you on here

Answer 7

can you send it to me on message?

Answer 8

Using the diagram and connecting the dots. The top horizontal line segment is y=b and the segment is the distance of the endpoints which is a-(-a) = 2a, the same goes for the bottom horizontal segment. The bottom is y=-b

The vertical segments on the left and right would be x=-a (left side) and x=a on the right.
The distance from the endpoints is b-(-b)=2b

Answer 9

So the rectangle formed has the dimensions of 2a X 2b

Answer 10

Thank you so much!
What about this one: verify that parallelogram ABCD with vertices A(-5,-1), B(-9,6), C(-1,5), D(3,-2) is a rhombus by showing that it is a parallelogram with perpendicular diagonals.

Answer 11

http://www.algebra.com/algebra/homework/Parallelograms/Parallelograms.faq.question.550000.html

i could explain it but this will explain it even better than i would :)

Answer 12

Thank you!
btw, great taste in music!

Answer 13

thanks their my favorite <3

Answer 14

anything else? you need help with i mean

Answer 15

No that's it. Thank you again!

Answer 16

your welcome glad i could help xD