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Chemistry 22 Online
OpenStudy (anonymous):

At equilibrium, what is the hydrogen-ion concentration if the acid dissociation constant is 0.000 001 and the acid concentration is 0.01M?

OpenStudy (abb0t):

K\(_a\) = 1.0 \(\times\)10\(\sf ^{-6}\) and [H\(^+\)]=0.01 M start by writing your equilibrium expression for the given dossociation reaction of the acid, [HA] \(\sf \color{blue}{HA \rightleftharpoons H^+ + A^- }\) Remember: K\(_a\)=\(\sf \frac{[products]}{[reactants]}\), and the concentration of the products are equal. So assume single variables for them, so you have [x][x] = [x\(^2\)]. And solve for it. Can you take it from here?

OpenStudy (anonymous):

yes thank you..that is what I was kindof thinking it was but I was not sure.

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