Question

Which of the following statements have the same result? Explain each step in solving each one.
I.f(2) when f(x) = 3x + 2
II.f-1(3) when f(x) = 2 x minus 7, all over 3
III.2y + 14 = 4y - 2

Answer 1

@ganeshie8

Answer 2

I really could use the help, I need a good grade:/

Answer 3

solve the variable in each statement

Answer 4

I don't get how to do that..that's what I need the help on

Answer 5

I.f(2) when f(x) = 3x + 2

find f(2) by putting x = 2

f(x) = 3x+2
f(2) = ?

Answer 6

f(2)= 2?

Answer 7

f of x is 3x+2
then f of 2 is 3(2)+2=8

Answer 8

Okay so f(2) = 3(2) + 2 = 8 now what?

Answer 9

so you have 1/ f(2) = 8 let it there
now, 2/ \(f^{-1}(3) \) when \(\large f(x )= \frac{2x-7}{3}\)
you have to find \(f^{-1}(x) \) which is \(\large \frac{3x+7}{2}\) and then \(f^{-1} (3) = 8\)
So, 1/ = 2
2/ = 8
now, 3/ solve for y : 2y+14 = 4y -2
16 = 2y
y = 8
Summary : 1/ = 2
2/ = 8
3/ =8
conclusion: 2/ and 3/ have the same solution.
Read it carefully, hopefully you can follow and know how to work on this kind of problem from now on. Good luck

Answer 10

oh, mistake, f(2 ) =8 , they are all equal. I am sorry.

Answer 11

So all the soutions are equal and have the same result?

Answer 12

yup

Answer 13

Thanks, so much

Answer 14

@Loser66 is wrong. Only 1 and 3 have the same result.

I. 3(2)+2
6+2
8

II. 2(3)-7/3
6-7/3
-1/3
-3

III. 2y+14 = 4y-2
16 = 2y
8 = y


ANSWER: I and III have the same result.

Answer 15

@Nico_dangond II is \(f^{-1}(3) \) , not just f (3) so that ,you must find inverse of f (x) first.