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Mathematics 14 Online
OpenStudy (anonymous):

k

OpenStudy (skullpatrol):

Any ideas where to start?

OpenStudy (anonymous):

i think the ones that are right are 1 3 5 and 6

OpenStudy (skullpatrol):

prove it

OpenStudy (skullpatrol):

$$\Huge x^3 + 3x^2 – 10x – 24$$

OpenStudy (skullpatrol):

How would you prove it?

OpenStudy (skullpatrol):

Are you still there @helpineedit ?

OpenStudy (skullpatrol):

If I gave you the number 10 and a list of numbers like 2, 3, 4, 5 and asked you to prove to me which ones are factors of 10? How would you do it?

OpenStudy (anonymous):

i would add it in the equation right?

OpenStudy (skullpatrol):

$$\frac{10}{2}=10\div2=5$$ So 2 is a factor of 10. $$\frac{10}{3}=10\div3=3 \text{ and remaider 1}$$ So 3 is not a factor because there is a remainder of 1 etc.

OpenStudy (skullpatrol):

Makes sense?

OpenStudy (skullpatrol):

factor: When two or more numbers are multiplied each of the numbers is a factor of the product.

OpenStudy (skullpatrol):

factors: numbers that are multiplied together to produce a product.

OpenStudy (skullpatrol):

2 and 5 are factors of 10 because 2 * 5 = 10. 3 is not a factor of 10 because no integer times 3 equals 10

OpenStudy (skullpatrol):

You should carefully read and fully understand what a factor is as defined above in the the two definitions I gave you @helpineedit ?

OpenStudy (skullpatrol):

$$\Huge\frac{ x^3 + 3x^2 – 10x – 24}{x-1} $$ $$\Huge=( x^3 + 3x^2 – 10x – 24) \div (x-1) $$

OpenStudy (anonymous):

ok

OpenStudy (skullpatrol):

If there is no remainder x-1 is a factor, if there is a remainder then it is not a factor.

OpenStudy (skullpatrol):

And of course the same goes for all the rest...

OpenStudy (anonymous):

the last one cant right?

OpenStudy (skullpatrol):

Test it and find out for sure.

OpenStudy (skullpatrol):

@helpineedit any questions?

OpenStudy (anonymous):

no thnx

OpenStudy (skullpatrol):

Thanks for asking :)

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