k
Any ideas where to start?
i think the ones that are right are 1 3 5 and 6
prove it
$$\Huge x^3 + 3x^2 – 10x – 24$$
How would you prove it?
Are you still there @helpineedit ?
If I gave you the number 10 and a list of numbers like 2, 3, 4, 5 and asked you to prove to me which ones are factors of 10? How would you do it?
i would add it in the equation right?
$$\frac{10}{2}=10\div2=5$$ So 2 is a factor of 10. $$\frac{10}{3}=10\div3=3 \text{ and remaider 1}$$ So 3 is not a factor because there is a remainder of 1 etc.
Makes sense?
factor: When two or more numbers are multiplied each of the numbers is a factor of the product.
factors: numbers that are multiplied together to produce a product.
2 and 5 are factors of 10 because 2 * 5 = 10. 3 is not a factor of 10 because no integer times 3 equals 10
You should carefully read and fully understand what a factor is as defined above in the the two definitions I gave you @helpineedit ?
$$\Huge\frac{ x^3 + 3x^2 – 10x – 24}{x-1} $$ $$\Huge=( x^3 + 3x^2 – 10x – 24) \div (x-1) $$
ok
If there is no remainder x-1 is a factor, if there is a remainder then it is not a factor.
And of course the same goes for all the rest...
the last one cant right?
Test it and find out for sure.
@helpineedit any questions?
no thnx
Thanks for asking :)
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