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What value completes the square for the expression?
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\[x ^{2}-16x\]
it is square of x-8 (x-8)^2=x^2-16x+64 so add 64
the answer is 64?
\[x^2-16x=0\]this?
yea
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ok thanks!
\[x^2-16x+8^2=0+8^2\]think of it like this.
The easy way to do it, for\[\Large ax^2 + bx\] is to divide b by 2, and square it:\[\Large \left( \frac{ b }{ 2 } \right)^2\] and you add that to both sides of the equation.
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