Select the pair of equations whose graphs are perpendicular.
A.
2y = –3x + 5
2x + 3y = 4
B.
y = 2x – 7
x + 2y = 3
C.
5x – 8y = 9
12x – 5y = 7
D.
x + 6y = 8
y = 2x – 8
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OpenStudy (anonymous):
@jim_thompson5910 @BlueEyedCountryGirl
jimthompson5910 (jim_thompson5910):
hint: two lines are perpendicular if their slopes multiply to -1
example:
y = 2x + 3
y = -1/2x + 7
are perpendicular because 2*(-1/2) = -1
OpenStudy (anonymous):
@jim_thompson5910 okay so what's the answer? Not trying to be rude.. haha
jimthompson5910 (jim_thompson5910):
sorry I can't just give out the answers, but I can help you get there
jimthompson5910 (jim_thompson5910):
are you able to solve for y?
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OpenStudy (anonymous):
Yeah well can you work through it with me?
jimthompson5910 (jim_thompson5910):
how would you solve 2y = –3x + 5 for y?
jimthompson5910 (jim_thompson5910):
how would you move that 2 over?
OpenStudy (anonymous):
that's the part I don't get...
OpenStudy (anonymous):
I mean I don't get the whole thing but this is also a problem.
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jimthompson5910 (jim_thompson5910):
well 2y means 2 times y
to move it over, you have to undo multiplication...so you have to divide both sides by 2
jimthompson5910 (jim_thompson5910):
\[\Large 2y = –3x + 5\]
\[\Large y = \frac{–3x + 5}{2}\]
\[\Large y = \frac{–3x}{2} + \frac{5}{2}\]
\[\Large y = -\frac{3}{2}x + \frac{5}{2}\]
What is the slope here?
OpenStudy (anonymous):
I honestly have no idea... sorry. I have a major gap from 5th grade till now.
jimthompson5910 (jim_thompson5910):
you're familiar with y = mx+b right? or no?
OpenStudy (anonymous):
sorry... no *winces*
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jimthompson5910 (jim_thompson5910):
that's ok, y = mx+b is the general form of any line where m is the slope and b is the y-intercept
jimthompson5910 (jim_thompson5910):
the slope determines how steep/shallow the line is
the y-intercept moves the line up and down
so these two uniquely determine a line
jimthompson5910 (jim_thompson5910):
compare \(\Large y = -\frac{3}{2}x + \frac{5}{2}\) to y = mx+b
what is m in this case?
OpenStudy (anonymous):
-3/2 ??
jimthompson5910 (jim_thompson5910):
good
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jimthompson5910 (jim_thompson5910):
now let's solve 2x + 3y = 4 for y
OpenStudy (anonymous):
Yayy! I'm honestly so proud right now. :)
jimthompson5910 (jim_thompson5910):
That's good. I'm glad you are. Let's solve the second equation for y.
\[\Large 2x + 3y = 4\]
\[\Large 3y = 4 - 2x\]
\[\Large 3y = -2x + 4\]
\[\Large y = \frac{-2x + 4}{3}\]
\[\Large y = \frac{-2x}{3} + \frac{4}{3}\]
\[\Large y = -\frac{2}{3}x + \frac{4}{3}\]
What is the slope here?
OpenStudy (anonymous):
I...don't know :/
jimthompson5910 (jim_thompson5910):
what is m in this case?
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jimthompson5910 (jim_thompson5910):
go back to y = mx+b
OpenStudy (anonymous):
okay give me a min.
jimthompson5910 (jim_thompson5910):
ok
OpenStudy (anonymous):
is it 2???
jimthompson5910 (jim_thompson5910):
compare \(\Large y = -\frac{2}{3}x + \frac{4}{3}\) to y = mx+b
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OpenStudy (anonymous):
oh so -2/3 ?
jimthompson5910 (jim_thompson5910):
yep, so the two slopes of the two equations are -3/2 and -2/3
jimthompson5910 (jim_thompson5910):
what do they multiply to?
OpenStudy (anonymous):
so multiply those?
OpenStudy (anonymous):
-1? or 1?
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jimthompson5910 (jim_thompson5910):
you have two negative numbers multiplied
jimthompson5910 (jim_thompson5910):
so is the result negative? or positive?
OpenStudy (anonymous):
1. Positive 1.
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
since the result is NOT -1, that means the two lines are NOT perpendicular
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