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@douglaswinslowcooper @jziggy
I dont quite understand how to evaluate this
oh and the upper bound is 3 it kinda got cut off
Ok... not sure how to best explain this one but the integral is the value between the function and the x-axis. The function has a max of 5 on the interval of 1 to 3 and a minimum of -2 on the interval. Since we're asked to find all the possible values of F on the interval we want to look at the extreme cases.
yes :) I understand that I just dont get how to go about it
and thank you for helping :)
Case I. The function is nearly equal to 5 for most of the time and only close to -2 for an extremely small time. In this case we could get an approximation by multiplying 5 by the Upper bound minus the Lower bound.
So 5(3-1)
is 10
Yes :)
And then we can get Case 2 in a similar way.
Case 2 The function is nearly equal to -2 for most of the time and only close to 5 for an extremely small time.
so im assuming the possible values are less than 10
Yes all possible values must be less than 10
-2(3-1) is -2*2 which is 4
so its choice A
-4<F<10
Yes :D
cool wana help with another?
Sure, what've you got?
just some solving integrals by substitution
Alright :D
ok
I have 10 more including this one to do before I take my final and I have to be done by 10pm :/ so yeah
Alright, so obviously we need to use a u-substitution on this problem. u = x^2 du = (2x)dx du/2 = (x)dx
yeah
So our new integral is|dw:1387585763984:dw|
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