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VECTORS: The vectors a b and c are such that a+b+c=0. Determine the value of a•b+a•c+b•c if |a|=1, |b|=2 and |c|=3.. here's my solution: http://sketchtoy.com/57497953
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can you please explain why did you do this: a²+b²+c²+2ab+2bc+2ac=0?
@RaphaelFilgueiras
(a+b+c)=0->(a+b+c)dot(a+b+c)=0=|a|²+|b|²+|c|²+2(a.b+b.c+a.c)
a.b is a (dot) b?
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yes
yes..
@RaphaelFilgueiras sorry, i still don't understand your method why did you transform (a+b+c)=0 into (a+b+c)dot(a+b+c)=0 ?? O.o sorry i'm a slow learner..
just because i want,and i can, zero is orthogonal to any vector, but multiply by itself will lead me to the answer.
you can multiply by anything, but that was a good choice
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