Question

prove cot-1 x = pi/2 - tan -1 x

Answer 1

could u plz draw out the equation?

Answer 2

\[\cot^{-1}x=\frac{π}{2}-\tan^{-1}x~~~~~~~~~~~~~~~~~~this?\]

Answer 3

yes as solomon put it

Answer 4

@SolomonZelman my brain won't function can u do this one xD

Answer 5

\[π=180°\]

Answer 6

still waiting for help :)

Answer 7

\[\huge\color{red}{ \frac{1}{Tan^{-1}x} +Tan^{-1}x } =90\]
\[\huge\color{red}{ Let~~~~Tan^{-1}x=a } \]
\[\huge\color{red}{ \frac{1}{a}+a=90 } \]\[\huge\color{red}{ 1+a^2=90a } \]\[a^2-90a+1=0\]

Answer 8

\[\huge\color{red}{ \frac{90±\sqrt{8100-4} }{2} } \]
\[\huge\color{red}{ \frac{90±94.95}{2} } \]
\[\huge\color{red}{ 45±47.475 } \]

Answer 9

\[\huge\color{red}{ Tan^{-1}x=-2.457 } \]\[\huge\color{red}{ Tan^{-1}x = +92.475 } \]

Answer 10

But this thing is so stupid though....

Answer 11

cot-1 x = pi/2 - tan -1 x
put cot on both sides, get
cot(cot-1 x) = cot(pi/2 - tan -1 x)
x = tan(tan-1 x)
x = x

:)

Answer 12

thanks solomon and Rad!! :D