Question

m

Answer 1

only the second three is under the radical

Answer 2

\(3tan^2(2x)-4\sqrt{3}tan(2x)+3=0\) right?

Answer 3

yes, that is correct

Answer 4

if I let tan (2x) = t and replace to it, what do we have?

Answer 5

I'm not entirely sure what you're asking there, what are we replacing? haha sorry

Answer 6

I let tan (2x) =t, so, wherever I see tan (2x) I put t there. Got me so far?

Answer 7

okay, you're substituting... alright i get that

Answer 8

so, now I have a quadratic, solve it, what do you have for t?
I rewrite it for you \(3t^2 - 4\sqrt{3}t +3=0\)

Answer 9

If I put it in the quadratic formula, I got x=1.73 and x=0.58

Answer 10

ok, it's t, not x, however, you know it, that's ok
plug it back to tan (2x) = t
first value: t = 1.73, so tan (2x) = 1.73 ---> 2x = arctan (1.73) =59.97 degree
so x = 59.97/2 = 29.99 degree
do the same with t = 0.58

Answer 11

sorry, t=.58=30.11 degrees

Answer 12

divided by 2 = 15.06

Answer 13

I think so

Answer 14

alright, now we have to figure what those numbers are in radians, right?

Answer 15

why do you have to do it? your prof ? but if you have to, it's not hard.

Answer 16

Yeah I have to write out my solutions to the equations in radians

Answer 17

Sorry. Did not notice that the problem was posted 8 days ago.
Refer to the attachment from Mathematica.