What is the equation of the line that passes through the point (2, 3) and is perpendicular to the line y = –x – 3?
what is the slope of line y = -x-3 ?
Would it be 2/3?
No, answer RadEn, what's the slope of y=-x-3?
What is the slope of y=mx+b? Can you google it and tell me what it is?
Oh the slope is -1
yes. Now if the slope of the original line is M, what is the slope of the line perpendicular to it?
It would be 1 since its the reciprocal of it right?
To find the slope of a line perpendicular, u find the negative reciprocal of the original slope. So in ur problem, to find the slope of the perpendicular line, u will find the negative reciprocal of -1 which is ....
Correct Algebra, the slope of the perpendicular line is the negative inverse of the original slope.
So you now know that the line passes through (2,3) and has slope of 1.
It would actually be 1/1 which is equal to 1
Now u can just plug that and the coordinates of the new line which is given in ur problem in the point slope equation
use the following formula: y-y1 = M(x-x1) where (2,3) is (x1, y1).
Really all you wanted to use from y = -x -3 is the slope, Then you would plug in y-y1=m(x-x1) (2,3) which is: y -2=1(x-3) can you solve now, the first step would be to apply distributive property to the 1(x-3)
So would it be (x+1)?
You're making a new equation, and putting it into y = mx + b form
What is 1 * x and 1 *(-3) @AlgebraOhNo
x and -3
1st, find the slope, m1, of y = –x – 3 by putting it in slope-intercept form. (That means solve for y) y = –x – 3 m1 = -1 The slope of lines perpendicular is the negative inverse of m1, = 1 Use y = mx + b and the point to find b. 3 = 1*2 + b b = 1 y = -x + 1 is thru (2,3) and perpendicular to y = –x – 3
Yes, x is the same as 1x so your new equation is; y-2=1x -3 what would you do now
Welcome to Openstudy @AlgebraOhNo
You would add the 2 to the right side so you would isolate the y and then you would have y=x-1
Thank you @Nurali
I would use 1x but its fine i guess
Okay thank you!
This is 9th grade math, right? I think i remember doing this :o
Im in 10th grade but yeah its Algebra 2