What is the equation of the line that passes through the point (2, 3) and is perpendicular to the line y = –x – 3?

Question

raden · Answer

what is the slope of line y = -x-3 ?

anonymous · Answer

Would it be 2/3?

agent47 · Answer

No, answer RadEn, what's the slope of y=-x-3?

anonymous · Answer

-3?

agent47 · Answer

What is the slope of y=mx+b? Can you google it and tell me what it is?

anonymous · Answer

Oh the slope is -1

agent47 · Answer

yes. Now if the slope of the original line is M, what is the slope of the line perpendicular to it?

anonymous · Answer

It would be 1 since its the reciprocal of it right?

nikato · Answer

To find the slope of a line perpendicular, u find the negative reciprocal of the original slope.
So in ur problem, to find the slope of the perpendicular line, u will find the negative reciprocal of -1 which is ....

anonymous · Answer

1

agent47 · Answer

Correct Algebra, the slope of the perpendicular line is the negative inverse of the original slope.

agent47 · Answer

So you now know that the line passes through (2,3) and has slope of 1.

the_fizicx99 · Answer

It would actually be 1/1 which is equal to 1

nikato · Answer

Now u can just plug that and the coordinates of the new line which is given in ur problem in the point slope equation

agent47 · Answer

use the following formula:
y-y1 = M(x-x1)
where (2,3) is (x1, y1).

the_fizicx99 · Answer

Really all you wanted to use from y = -x -3 is the slope,

Then you would plug in y-y1=m(x-x1)   (2,3)

which is: y -2=1(x-3)   can you solve now, the first step would be to apply distributive property to the 1(x-3)

anonymous · Answer

So would it be (x+1)?

the_fizicx99 · Answer

You're making a new equation, and putting it into y = mx + b form

the_fizicx99 · Answer

What is 1 * x and 1 *(-3) @AlgebraOhNo

anonymous · Answer

x and -3

nurali · Answer

1st, find the slope, m1, of y = –x – 3 by putting it in slope-intercept form. (That means solve for y)
y = –x – 3
m1 = -1

The slope of lines perpendicular is the negative inverse of m1, = 1
Use y = mx + b and the point to find b.
3 = 1*2 + b
b = 1
y = -x + 1 is thru (2,3) and perpendicular to y = –x – 3

the_fizicx99 · Answer

Yes, x is the same as 1x so your new equation is; y-2=1x -3  what would you do now

nurali · Answer

Welcome to Openstudy @AlgebraOhNo

anonymous · Answer

You would add the 2 to the right side so you would isolate the y and then you would have y=x-1

the_fizicx99 · Answer

Yup

anonymous · Answer

Thank you @Nurali

the_fizicx99 · Answer

I would use 1x but its fine i guess

nurali · Answer

Anytime.

anonymous · Answer

Okay thank you!

the_fizicx99 · Answer

This is 9th grade math, right? I think i remember doing this :o

anonymous · Answer

Im in 10th grade but yeah its Algebra 2

the_fizicx99 · Answer

oh