Question

How would you find the equation of a line in standard form and slope-intercept form, that passes through (-1,5) and (1,9)?

Answer 1

M = y2-y1/x2-x1

plug in values

Answer 2

That'll give you your slope :p

Answer 3

So the slope is 2?

Answer 4

Well, 9-5 = 4

1-(-1) = 2

so 4/2 = 2 yes

Answer 5

So naw that you have your slope, put it into y-y1=M(x-x1)

Answer 6

The equation would be y=2x+7 then right?

Answer 7

So its: y-1=2(x-(-1)

y-1=2x +2
+1 +1

y=2x + 3

Answer 8

How did you get 7 lol xD

Answer 9

@AlgebraOhNo

Answer 10

Oh I put in a wrong value, for the y1 I put in 5 by accident

Answer 11

ah kay

Answer 12

Do you know what standard form is?

Answer 13

Isn't that ax^2+bx+c?

Answer 14

Thats quadratic xD Ax + By = C

Answer 15

So how would you convert y = 2x +3 into Ax + By = C

Answer 16

@AlgebraOhNo

Answer 17

On a side note, do you know how to do quadratic? :O

Answer 18

No not really

Answer 19

Not really as in for Ax + by = c or the quad thingy i asked lol <- descriptive

Answer 20

The quadratic one

Answer 21

Oh lol kk, well that was irrelevant to this so, to convert y = 2x + 3 you would subtract 2x from both sides and get -2x + y = 3 .... in most cases you would multiply by -1 to get the x coefficient positive

Answer 22

And that would be the standard form of the equation?

Answer 23

Idk some teachers allow the x coefficient to be negative, some require you to multiply is by -1 to make it positive

Answer 24

So if I were to turn it positive it would be 2x-y=-3

Answer 25

If you'd like you just have to multiply every term by -1

-2x(-1) +y(-1) = 3(-1)

Answer 26

Yesh :3

Answer 27

Usually its A>0

Answer 28

Okay, thank you so much!

Answer 29

no prob yw :}