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Sigma notation help please?
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Use sigma notation to write the sum: [1 - (2/n - 1)^2](2/n) + ... + [1 - (2n/n - 1)^2](2/n)
[1 - (2/n - 1)^2](2/n) and [1 - (2n/n - 1)^2](2/n) are different equations... are they suppose to be?
Yes.
I am super confused on how to do this.
i'll try and help ^_^ so, lets look at the first part only, can you turn [1 - (2/n - 1)^2](2/n) + ... into sigma notation?
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I don't know how.
@DemolisionWolf
[1 - (2/n - 1)^2](2/n) \[\sum_{n=1}^{\infty} \frac{2(1 - (\frac{2}{n} - 1)^2)}{n}\]
@DemolisionWolf Is that the whole thing or just the first part?
to be honest, i'm not 100% sure on all of this, but that is what I would put as my answer.
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Okay thankyou!
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