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Find the equation of a parabola with focus F(0, -12) and directrix y = 12.
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@Timotheos
Can u help plz
Any point, (x, y) on the parabola satisfies the definition of parabola, so there are two distances to calculate: Distance between the point on the parabola to the focus (a,b) Distance between the point on the parabola to the directrix (y=c) when we equate the SQUARE of these distances, we get \(\large (x-a)^2 + (y-k)^2 = (y-c)^2\) for your question, a = 0, b = -12 , c = 12 just plug in and simplify!
** \(\large (x-a)^2 + (y-b)^2 = (y-c)^2\)
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x^2 + (y+12)^2 = (y-12)^2 see whether you get x^2 = -48y or y = (-1/48)x^2 (which is your choice A)
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