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Mathematics 22 Online
OpenStudy (anonymous):

__ What is the length of BC approximated to the nearest tenth? A. 11 B. 13 C. 14 D. 16

OpenStudy (anonymous):

OpenStudy (anonymous):

6x-50=x+5

OpenStudy (anonymous):

6x-50=x+5 -x -x 5x -50 =5 +50 +50 5x=55

OpenStudy (anonymous):

55 divided by 5 is ?

OpenStudy (anonymous):

@KingGeorge @satellite73 @phi don't suspend me

OpenStudy (anonymous):

11

OpenStudy (anonymous):

Correct x= 11

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

@arilove1d 2 more

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

A 30°-60°-90° triangle has a hypotenuse with a length of 10. What is the length of the longer leg of the triangle?

OpenStudy (anonymous):

a 5 b 5 cubed c square root 5 d 20

OpenStudy (anonymous):

Rule for all 30°-60°-90° triangles: 1. The hypotenuse is twice the shorter leg. 2. The longer leg is sqrt3 times the shorter leg.

OpenStudy (ranga):

Note: For the first problem x = 11 (and not the answer). You need to find the length of BC by plugging in the x value.

OpenStudy (anonymous):

2x10=?

OpenStudy (anonymous):

20

OpenStudy (anonymous):

What is the value of x?

OpenStudy (anonymous):

please help

OpenStudy (anonymous):

Im mot really sure i dont want to give you a wrong answer

OpenStudy (anonymous):

it's alright i'm in the safe zone u can give a wrong one

OpenStudy (shamil98):

\[6x - 50 = x + 5\] \[5x = 55\] As Ranga mentioned you need to evaluate the length of BC, all we did is find the value of x. \[BC = x + 5 ==> BC = 55 + 5 = 60\]

OpenStudy (shamil98):

For your second problem, You use the sine function. \[\huge \sin {\theta} = \frac{ opp }{ hyp }\] \[\sin 60^{o} = \frac{ x }{ 16 }\] Evaluate sin at 60 degrees, and then solve for x.

OpenStudy (ranga):

First problem. x = 11, BC = x + 5 = 11 + 5 = 16. Answer is D.

OpenStudy (shamil98):

oh oops i made an error there , x = 11, >.<

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