Question

2a(a-5)+4(a-5)

Answer 1

Hint: (a-5) is the common factor :)

Answer 2

Always take out the common factor :)

Answer 3

\[\huge 2a(a-5) + 4(a-5)\]
Distribute.
\[\huge 2a^2 - 10a + 4a - 20\]
Simplify.
\[\huge 2a^2 - 6a - 20\]
\[\huge 2(a^2 -3a + 10)\]
\[\huge 2(a-5)(a+2)\]

Answer 4

oops i changed the sign there

Answer 5

\[\huge 2(a^2 -3a - 10)\]
\[\huge 2(a-5)(a+2)\]
is the correct factor though

Answer 6

lolz he's gone

Answer 7

yep

Answer 8

Why did you distribute @shamil98 ?
kc_kennylau's method is only two steps

2a(a-5)+4(a-5)
(2a+4)(a-5)
2(a+2)(a-5)

Answer 9

2a(a-5)+4(a-5)

Multiply 2a by each term inside the parentheses.
2a^(2)-10a+4(a-5)

Multiply 4 by each term inside the parentheses.
2a^(2)-10a+4a-20

Since -10a and 4a are like terms, subtract 4a from -10a to get -6a.
2a^(2)-6a-20