Question

Given the functions f(n) = 11 and g(n) = (three over four)n − 1, combine them to create a geometric sequence, an, and solve for the 9th term.

Answer 1

@shamil98

Answer 2

\[f(n) = 11 ~~~g(n) = \frac {3}{4} n-1\]
I'm not too sure how you would combine them to make a sequence..

Answer 3

You would just add them right?

Answer 4

an = 11(three fourths)n − 1; a9 ≈ 1.101

Answer 5

this seems like the most accurate option

Answer 6

let h(n) = f(n) + g(n)
\[h(n) = \frac{ 3n-3 }{ 4 }+11\]

Answer 7

\[h(9) = \frac{ 3(9-1) }{ 4 } + 11\]
\[h(9) = \frac{ 24 }{ 4 } + 11 = 6 + 11 = 17\]

Answer 8

This is just my guess.

Answer 9

Is h(n) a geometric sequence? @shamil98 and Why?

Answer 10

an = (11 • three fourths)n − 1; a9 ≈ 24.301

an = 11(three fourths)n − 1; a9 ≈ 1.101

an = 11 + (three fourths)n − 1; a9 ≈ 11.100

an = 11 − (three fourths)n − 1; a9 ≈ 9.900
these are the options

Answer 11

Oh, h(n) would be an arithmetic sequence, the difference between terms is .75.

Answer 12

They are asking to get a geometric sequence

Answer 13

@eliassaab Which one looks like the right one to you?

Answer 14

Yeah, so you can cross out options C and D then..

Answer 15

i think its B

Answer 16

I think it would be option B.

Answer 17

What are the options C and D?

Answer 18

an = (11 • three fourths)n − 1; a9 ≈ 24.301

an = 11(three fourths)n − 1; a9 ≈ 1.101

an = 11 + (three fourths)n − 1; a9 ≈ 11.100

an = 11 − (three fourths)n − 1; a9 ≈ 9.900

Answer 19

Is it (3/4n) -1
or (3/4) * n-1
?

Answer 20

thanks @shamil98 B was correct!!

Answer 21

B is not a geometric series.

Answer 22

The question is asking for a sequence not a series.

Answer 23

'Twas corrrect. :)