This is a neat question that I was asked back after 5th grade to get into an advanced math program, thought I'd offer it for the holidays. Find a 10 digit number such that the 1st digit in the number tells how many 0's there are in the number, the second digit tells how many 1's are in the number, the third digit tells how many 2, etc. all the way to the tenth digit tells how many 9s there are in the number. Hint: There is only one solution.
:L
The digits add up to ten am i correct
Yep
ohhhhhhhh
(since there are 10 digits, that's a good first conclusion) :)
7210000100
OH YEAH I DID THIS MYSELF
so close, but not quite there aren't 7 0's :)
wait something wrong
6210001000
DONE
Yep :)
im stupid at maths
and that was like simple
Thought process: 9,000,000,000-> 9,000,000,001-> 9,100,000,001-> 8,210,000,010-> 7,210,000,100-> 6,210,001,000
My logic on this one was to realize there had to be a large number of 0s, so I put an x in the zero's column. That means there needs to be 1 x. So there has to be at least 1 1, but then there'd be 2 1s, so it's actually a 2 in the 1's column, a 1 in the 2's columnh, a 1 in the x column, anc an x in the 0's columnh, leaving 6 0s for x :)
And yeah, basically the same thought process, algebraicallly
algebra is just for presentation, when i think i think in real numbers :)
this stinks i hate maths
RAGE
Real numbers are an icky space to work in. I prefer the complex numbers, so much more sensible :)
@missMob here's a medal to calm you down :D
lol thx
@farabor I meant "real number" as not variables
Anyhow, closing this one down. Hopefully something new and interesting will occur to someone :)
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