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OpenStudy (annie96):
2. 5 ( 3 – m) + 5m = 15
3. -2 |x| - 7 = -3
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OpenStudy (annie96):
1.) 4-2y=2(9-y)
2y=2+(-18y)
2y=-16y
y=-8
OpenStudy (annie96):
no
OpenStudy (zpupster):
2(9-y )= 18-2y by distributive property
OpenStudy (bibby):
Expand it out using the distributive property as zpup just did
5( 3 – m) + 5m = 15
(5*3)-(5*m)+(5m) = 15
OpenStudy (anonymous):
The three equations are trick equations.
4 - 2 y = 2 (9 - y)
4 - 2 y = 18 - 2 y
4 != 18
5 (3 - m) + 5 m == 15
15 - 5 m + 5 m == 15
15 = 15
-7 - 2 Abs[x] == -3
Abs[x] != -2
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OpenStudy (anonymous):
Sorry. == is = in Mathematica. Did not edit the last two solutions.
OpenStudy (bibby):
Just so we're clear != == =/= || ≠:)
OpenStudy (anonymous):
!= "not equal"
== "equal"
OpenStudy (bibby):
this was programming humor yes thank
OpenStudy (anonymous):
@bibby
Ha Ha. Very clever. I happen to be a former programmer.
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OpenStudy (annie96):
How do you solve number 3.
OpenStudy (anonymous):
-7 - 2 Abs[x] = -3
- 2 Abs[x] = 7-3
- 2 Abs[x] = 4
Abs[x] = 4/(- 2)
Abs[x] ≠ -2
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