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Mathematics 23 Online
OpenStudy (anonymous):

I have a radical question that I need help with

OpenStudy (anonymous):

OpenStudy (anonymous):

I'll help you with that

OpenStudy (anonymous):

you are allowed to get both the numerator and the denominator under ONE sqrt so you simple do 108/6=18=2*3^2 Then you simlify x^5/x = x^4 and y^8/y^5=y^3 and you get 3*sqrt(2 x^4 y^3)

OpenStudy (anonymous):

can you make it under the equation button on the bottom of the left side, so its easier for me to understand

OpenStudy (anonymous):

you can alsoget x^2 outside of sqrt so you have 3x^2 sqrt(2y^3)

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Ok! Give me a sec because i haven't used it

OpenStudy (anonymous):

ok tyy

OpenStudy (anonymous):

\[\frac{ \sqrt{108x^5y^8} }{ \sqrt{6xy^5} } = \sqrt\frac{ 108x^5y^8 }{ 6xy^5 }\]

OpenStudy (anonymous):

ok then after that

OpenStudy (kc_kennylau):

Use the laws of indices after that

OpenStudy (anonymous):

You can simplify after that till you get \[3x^2\sqrt{2y^3}\]

OpenStudy (anonymous):

And that's the most simplified it can get

OpenStudy (anonymous):

I have to do step by step

OpenStudy (anonymous):

hmmm do you get that \[\frac{ x^5 }{ x } = x^4\]

OpenStudy (anonymous):

okok

OpenStudy (anonymous):

Do the same for y

OpenStudy (anonymous):

ok ty

OpenStudy (anonymous):

\[\sqrt{\frac {108}{6}} = \sqrt{18} = \sqrt{2*9} = 3\sqrt{2}\]

OpenStudy (anonymous):

ty

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